Ответ:
Приводим дроби к общему знаменателю. Если дробная часть уменьшаемого меньше вычитаемой, занимаем одну единицу из целой части.
- \(1-\frac{7}{9}=\frac{9}{9}-\frac{7}{9}=\frac{2}{9}\).
- \(3-\frac{4}{5}=2+\frac{5}{5}-\frac{4}{5}=2\frac{1}{5}\).
- \(8-2\frac{1}{6}=6-\frac{1}{6}=5\frac{5}{6}\).
- \(5-4\frac{2}{3}=1-\frac{2}{3}=\frac{1}{3}\).
- \(6\frac{3}{4}-\frac{5}{8}=6\frac{6}{8}-\frac{5}{8}=6\frac{1}{8}\).
- \(3\frac{5}{6}-\frac{4}{9}=3+\frac{15}{18}-\frac{8}{18}=3\frac{7}{18}\).
- \(9\frac{11}{16}-\frac{7}{24}=9+\frac{33}{48}-\frac{14}{48}=9\frac{19}{48}\).
- \(4\frac{15}{49}-\frac{3}{14}=4+\frac{30}{98}-\frac{21}{98}=4\frac{9}{98}\).
- \(5\frac{7}{12}-2\frac{2}{15}=3+\frac{35}{60}-\frac{8}{60}=3\frac{9}{20}\).
- \(4\frac{11}{14}-3\frac{2}{7}=1+\frac{11}{14}-\frac{4}{14}=1\frac{1}{2}\).
- \(3\frac{13}{44}-1\frac{7}{33}=2+\frac{39}{132}-\frac{28}{132}=2\frac{11}{132}\).
- \(9\frac{11}{60}-3\frac{13}{80}=6+\frac{44}{240}-\frac{39}{240}=6\frac{1}{48}\).
- \(2\frac{3}{5}-1\frac{6}{7}=\frac{13}{5}-\frac{13}{7}=\frac{91-65}{35}=\frac{26}{35}\).
- \(10\frac{1}{3}-5\frac{4}{9}=5+\frac{3}{9}-\frac{4}{9}=4\frac{8}{9}\).
- \(8\frac{4}{13}-3\frac{9}{26}=5+\frac{8}{26}-\frac{9}{26}=4\frac{25}{26}\).
- \(7\frac{4}{25}-2\frac{3}{4}=5+\frac{16}{100}-\frac{75}{100}=4\frac{41}{100}\).
