Решение:
- а) \(\frac{5}{6} + \frac{1}{4} = \frac{5 \cdot 2}{12} + \frac{1 \cdot 3}{12} = \frac{10 + 3}{12} = \frac{13}{12} = 1\frac{1}{12}\)
- б) \(\frac{11}{18} \cdot \frac{36}{7} = \frac{11 \cdot 36}{18 \cdot 7} = \frac{11 \cdot 2}{7} = \frac{22}{7} = 3\frac{1}{7}\)
- в) \(\frac{15}{17}:5 = \frac{15}{17 \cdot 5} = \frac{3}{17}\)
- г) \(3,8 + (-7,3) = 3,8 - 7,3 = -3,5\)
- д) \(-2,8 - 5,3 = -(2,8 + 5,3) = -8,1\)
- е) \(-6\frac{3}{4} \cdot \left(-1\frac{11}{45}\right) = \left(-\frac{27}{4}\right) \cdot \left(-\frac{56}{45}\right) = \frac{27 \cdot 56}{4 \cdot 45} = \frac{3 \cdot 14}{1 \cdot 5} = \frac{42}{5} = 8\frac{2}{5}\)
- ж) \(1,632:(-1,6) = -1,02\)
Ответ: а) \(1\frac{1}{12}\); б) \(3\frac{1}{7}\); в) \(\frac{3}{17}\); г) \(-3,5\); д) \(-8,1\); е) \(8\frac{2}{5}\); ж) \(-1,02\).