202. Вычислите: а) 5 2/5 · 1 1/9 − 4 4/7 · 1 3/4; б) 7 1/3 : 1 2/9 + 4 8/9 · 9/11; в) 2 1/3 : (2 − 17 1/3 : 13); г) (3 3/8 · 1 7/9 − 3) : 3/5.

а)

Преобразуем смешанные числа в неправильные дроби:

\(5\frac{2}{5}=\frac{27}{5}\), \(1\frac{1}{9}=\frac{10}{9}\), \(4\frac{4}{7}=\frac{32}{7}\), \(1\frac{3}{4}=\frac{7}{4}\).

\[\frac{27}{5}\cdot\frac{10}{9}-\frac{32}{7}\cdot\frac{7}{4}=6-8=-2\]

б)

\[7\frac{1}{3}:1\frac{2}{9}+4\frac{8}{9}\cdot\frac{9}{11}=\frac{22}{3}:\frac{11}{9}+\frac{44}{9}\cdot\frac{9}{11}\]

\[\frac{22}{3}\cdot\frac{9}{11}+4=6+4=10\]

в)

\[2\frac{1}{3}:\left(2-17\frac{1}{3}:13\right)=\frac{7}{3}:\left(2-\frac{52}{3}:13\right)\]

\[\frac{52}{3}:13=\frac{4}{3},\qquad 2-\frac{4}{3}=\frac{2}{3}\]

\[\frac{7}{3}:\frac{2}{3}=\frac{7}{3}\cdot\frac{3}{2}=\frac{7}{2}=3\frac{1}{2}\]

г)

\[\left(3\frac{3}{8}\cdot1\frac{7}{9}-3\right):\frac{3}{5}=\left(\frac{27}{8}\cdot\frac{16}{9}-3\right):\frac{3}{5}\]

\[\left(6-3\right):\frac{3}{5}=3\cdot\frac{5}{3}=5\]

Ответ: а) \(-2\); б) \(10\); в) \(3\frac{1}{2}\); г) \(5\).