Ответ:

1) \(\left(-\frac{7}{18}+\frac{11}{12}\right):\left(-\frac{19}{48}\right)=\left(-\frac{14}{36}+\frac{33}{36}\right):\left(-\frac{19}{48}\right)=\frac{19}{36}\cdot\left(-\frac{48}{19}\right)=-\frac{4}{3}\).

2) \(\left(\frac{7}{16}+\frac{5}{24}\right):\left(-1\frac{15}{16}\right)=\frac{31}{48}:\left(-\frac{31}{16}\right)=\frac{31}{48}\cdot\left(-\frac{16}{31}\right)=-\frac{1}{3}\).

3) \(\left(-3\frac{5}{12}-2\frac{4}{15}\right):\left(-6\frac{3}{20}\right)=\left(-\frac{41}{12}-\frac{34}{15}\right):\left(-\frac{123}{20}\right)=\left(-\frac{341}{60}\right)\cdot\left(-\frac{20}{123}\right)=\frac{341}{369}\).

4) \(\left(\frac{10}{21}-\frac{25}{28}\right):\left(-\frac{11}{14}+\frac{24}{35}\right)=\left(-\frac{5}{12}\right):\left(-\frac{1}{10}\right)=\frac{25}{6}\).

5) \(-4{,}8:\frac{4}{15}=-\frac{24}{5}\cdot\frac{15}{4}=-18\). Поэтому \(-15\frac{3}{7}-(-18)=-\frac{108}{7}+18=\frac{18}{7}\). Тогда \(-2\frac{2}{3}+2\frac{1}{3}\cdot\frac{18}{7}=-\frac{8}{3}+\frac{7}{3}\cdot\frac{18}{7}=-\frac{8}{3}+6=\frac{10}{3}\).

Ответ: 1) \(-\frac{4}{3}\); 2) \(-\frac{1}{3}\); 3) \(\frac{341}{369}\); 4) \(\frac{25}{6}\); 5) \(\frac{10}{3}\).