Ответ:

  1. \(4\frac{8}{9}+1\frac{1}{6}=5+\frac{16}{18}+\frac{3}{18}=5\frac{19}{18}=6\frac{1}{18}\).
  2. \(7\frac{3}{8}-4\frac{1}{4}=3+\frac{3}{8}-\frac{2}{8}=3\frac{1}{8}\).
  3. \(2\frac{3}{4}-1\frac{1}{6}=1+\frac{9}{12}-\frac{2}{12}=1\frac{7}{12}\).

Ответ: а) \(6\frac{1}{18}\); б) \(3\frac{1}{8}\); в) \(1\frac{7}{12}\).