$$\frac{2^3 \cdot (2^{12})^5}{2^{56} \cdot 2^4} = \frac{2^3 \cdot 2^{12 \cdot 5}}{2^{56+4}} = \frac{2^3 \cdot 2^{60}}{2^{60}} = \frac{2^{3+60}}{2^{60}} = \frac{2^{63}}{2^{60}} = 2^{63-60} = 2^3 = 8$$.
Ответ: $$8$$