Ответ:
Правило: смешанное число \(a\frac{b}{c}\) переводим в неправильную дробь по формуле \(a\frac{b}{c}=\frac{ac+b}{c}\).
А: \(\frac{11}{7};\ \frac{31}{10};\ \frac{23}{14};\ \frac{25}{11};\ \frac{507}{100};\ \frac{263}{100};\ \frac{39}{10};\ \frac{37}{6};\ \frac{7}{9};\ \frac{4}{13}\).
Б: \(\frac{15}{7};\ \frac{29}{13};\ \frac{17}{9};\ \frac{37}{10};\ \frac{23}{12};\ \frac{14}{3};\ \frac{151}{100};\ \frac{51}{10};\ \frac{37}{11};\ \frac{29}{10};\ \frac{73}{14};\ \frac{67}{15};\ \frac{12}{5};\ \frac{309}{100};\ \frac{30}{11}\).
В: \(\frac{9}{2};\ \frac{34}{11};\ \frac{70}{13};\ \frac{10}{7};\ \frac{57}{10};\ \frac{25}{12};\ \frac{32}{9};\ \frac{191}{100};\ \frac{19}{8};\ \frac{41}{10};\ \frac{11}{6};\ \frac{13}{5};\ \frac{403}{100};\ \frac{40}{11};\ \frac{19}{10}\).
Г: \(\frac{16}{3};\ \frac{54}{13};\ \frac{311}{100};\ \frac{13}{10};\ \frac{21}{8};\ \frac{27}{10};\ \frac{25}{14};\ \frac{20}{9};\ \frac{57}{11};\ \frac{51}{13};\ \frac{237}{100};\ \frac{9}{5};\ \frac{49}{10};\ \frac{47}{7};\ \frac{49}{15}\).
Д: \(\frac{25}{18};\ \frac{79}{10};\ \frac{41}{7};\ \frac{32}{13};\ \frac{31}{5};\ \frac{43}{11};\ \frac{10}{9};\ \frac{67}{10};\ \frac{219}{100};\ \frac{21}{4};\ \frac{17}{11};\ \frac{23}{10};\ \frac{29}{7};\ \frac{75}{14};\ \frac{313}{100}\).
Е: \(\frac{31}{12};\ \frac{33}{10};\ \frac{20}{11};\ \frac{543}{100};\ \frac{22}{9};\ \frac{92}{15};\ \frac{23}{7};\ \frac{20}{13};\ \frac{27}{11};\ \frac{29}{14};\ \frac{7}{4};\ \frac{59}{10};\ \frac{19}{5};\ \frac{427}{100};\ \frac{17}{10}\).
