Решение:
Для сокращения дробей нужно найти наибольший общий делитель (НОД) числителя и знаменателя и разделить оба числа на него.
- \( \frac{12}{14} = \frac{12 \div 2}{14 \div 2} = \frac{6}{7} \)
- \( \frac{8}{34} = \frac{8 \div 2}{34 \div 2} = \frac{4}{17} \)
- \( \frac{42}{48} = \frac{42 \div 6}{48 \div 6} = \frac{7}{8} \)
- \( \frac{35}{45} = \frac{35 \div 5}{45 \div 5} = \frac{7}{9} \)
- \( \frac{32}{80} = \frac{32 \div 16}{80 \div 16} = \frac{2}{5} \)
- \( \frac{28}{63} = \frac{28 \div 7}{63 \div 7} = \frac{4}{9} \)
- \( \frac{24}{32} = \frac{24 \div 8}{32 \div 8} = \frac{3}{4} \)
- \( \frac{51}{68} = \frac{51 \div 17}{68 \div 17} = \frac{3}{4} \)
- \( \frac{49}{91} = \frac{49 \div 7}{91 \div 7} = \frac{7}{13} \)
- \( \frac{60}{75} = \frac{60 \div 15}{75 \div 15} = \frac{4}{5} \)
- \( \frac{63}{81} = \frac{63 \div 9}{81 \div 9} = \frac{7}{9} \)
- \( \frac{18}{45} = \frac{18 \div 9}{45 \div 9} = \frac{2}{5} \)
- \( \frac{55}{77} = \frac{55 \div 11}{77 \div 11} = \frac{5}{7} \)
- \( \frac{63}{72} = \frac{63 \div 9}{72 \div 9} = \frac{7}{8} \)
- \( \frac{30}{45} = \frac{30 \div 15}{45 \div 15} = \frac{2}{3} \)
- \( \frac{24}{28} = \frac{24 \div 4}{28 \div 4} = \frac{6}{7} \)
- \( \frac{45}{72} = \frac{45 \div 9}{72 \div 9} = \frac{5}{8} \)
- \( \frac{49}{56} = \frac{49 \div 7}{56 \div 7} = \frac{7}{8} \)
- \( \frac{36}{76} = \frac{36 \div 4}{76 \div 4} = \frac{9}{19} \)
- \( \frac{65}{91} = \frac{65 \div 13}{91 \div 13} = \frac{5}{7} \)
- \( \frac{35}{65} = \frac{35 \div 5}{65 \div 5} = \frac{7}{13} \)
- \( \frac{36}{84} = \frac{36 \div 12}{84 \div 12} = \frac{3}{7} \)
- \( \frac{28}{70} = \frac{28 \div 14}{70 \div 14} = \frac{2}{5} \)
- \( \frac{20}{85} = \frac{20 \div 5}{85 \div 5} = \frac{4}{17} \)
- \( \frac{56}{72} = \frac{56 \div 8}{72 \div 8} = \frac{7}{9} \)
- \( \frac{36}{45} = \frac{36 \div 9}{45 \div 9} = \frac{4}{5} \)
- \( \frac{24}{68} = \frac{24 \div 4}{68 \div 4} = \frac{6}{17} \)
- \( \frac{64}{72} = \frac{64 \div 8}{72 \div 8} = \frac{8}{9} \)
- \( \frac{30}{85} = \frac{30 \div 5}{85 \div 5} = \frac{6}{17} \)
- \( \frac{52}{65} = \frac{52 \div 13}{65 \div 13} = \frac{4}{5} \)
- \( \frac{35}{56} = \frac{35 \div 7}{56 \div 7} = \frac{5}{8} \)
- \( \frac{48}{54} = \frac{48 \div 6}{54 \div 6} = \frac{8}{9} \)
- \( \frac{26}{65} = \frac{26 \div 13}{65 \div 13} = \frac{2}{5} \)
- \( \frac{56}{96} = \frac{56 \div 8}{96 \div 8} = \frac{7}{12} \)
- \( \frac{9}{39} = \frac{9 \div 3}{39 \div 3} = \frac{3}{13} \)
- \( \frac{27}{36} = \frac{27 \div 9}{36 \div 9} = \frac{3}{4} \)
- \( \frac{16}{68} = \frac{16 \div 4}{68 \div 4} = \frac{4}{17} \)
- \( \frac{26}{39} = \frac{26 \div 13}{39 \div 13} = \frac{2}{3} \)
- \( \frac{60}{84} = \frac{60 \div 12}{84 \div 12} = \frac{5}{7} \)
- \( \frac{49}{63} = \frac{49 \div 7}{63 \div 7} = \frac{7}{9} \)
- \( \frac{18}{21} = \frac{18 \div 3}{21 \div 3} = \frac{6}{7} \)
Ответ: в ячейках приведены сокращённые дроби.