\[ \frac{3}{5} - \frac{7}{2} = \frac{3 \times 2}{5 \times 2} - \frac{7 \times 5}{2 \times 5} = \frac{6}{10} - \frac{35}{10} = \frac{6 - 35}{10} = \frac{-29}{10} \]
\[ \frac{3}{7} + 1\frac{1}{3} = \frac{3}{7} + \frac{1 \times 3 + 1}{3} = \frac{3}{7} + \frac{4}{3} = \frac{3 \times 3}{7 \times 3} + \frac{4 \times 7}{3 \times 7} = \frac{9}{21} + \frac{28}{21} = \frac{9 + 28}{21} = \frac{37}{21} \]
\[ \frac{29}{4} : \left( \frac{-29}{10} \right) = \frac{29}{4} \times \left( \frac{10}{-29} \right) = \frac{29 \times 10}{4 \times (-29)} = \frac{10}{-4} = \frac{-5}{2} \]
\[ \frac{37}{21} : \left( \frac{-74}{21} \right) = \frac{37}{21} \times \left( \frac{21}{-74} \right) = \frac{37 \times 21}{21 \times (-74)} = \frac{37}{-74} = \frac{1}{-2} = \frac{-1}{2} \]
\[ \frac{-5}{2} + \left( \frac{-1}{2} \right) = \frac{-5}{2} - \frac{1}{2} = \frac{-5 - 1}{2} = \frac{-6}{2} = -3 \]
Ответ: -3