з) −3\(\frac{11}{20}\) + \(−2\frac{19}{30}\)= -3\(\frac{11}{20}\) - 2\(\frac{19}{30}\)= -3\(\frac{11 \cdot 3}{20 \cdot 3}\) - 2\(\frac{19 \cdot 2}{30 \cdot 2}\) = -3\(\frac{33}{60}\) - 2\(\frac{38}{60}\) = -\(3\frac{33}{60} + 2\frac{38}{60}\) = -\(5 + \frac{33+38}{60}\) =
= -\(5 + \frac{71}{60}\) = -\(5+1\frac{11}{60}\) = -6\(\frac{11}{60}\)
Ответ: -6\(\frac{11}{60}\)