3) \(\frac{\sqrt{22} \cdot \sqrt{33}}{\sqrt{6}}\)

1. \(\frac{\sqrt{2 \cdot 11} \cdot \sqrt{3 \cdot 11}}{\sqrt{2 \cdot 3}}\) = \(\frac{\sqrt{2} \cdot \sqrt{11} \cdot \sqrt{3} \cdot \sqrt{11}}{\sqrt{2} \cdot \sqrt{3}}\).
2. \(\sqrt{11}\) \(\cdot\) \(\sqrt{11}\) = 11.
3. \(\text{Ответ: }\) 11.