Ответ:\(\sqrt[3]{8x^6}=2x^2\).\(\sqrt{\frac{1}{4}x^2y^4}=\frac{|x|y^2}{2}\).\(\sqrt[3]{\frac{1}{27}a^3b^9}=\frac{ab^3}{3}\).\(\sqrt[4]{a^4b^8c^{12}}=|a|b^2|c|^3\).