Ответ:

Преобразуем смешанные числа:

\(13\frac{2}{3} = \frac{41}{3}\), \(1\frac{1}{6} = \frac{7}{6}\), \(2\frac{1}{4} = \frac{9}{4}\).

\(\frac{7}{6} + \frac{9}{4} = \frac{14}{12} + \frac{27}{12} = \frac{41}{12}\).

\(\frac{41}{3} : \frac{41}{12} = \frac{41}{3} \cdot \frac{12}{41} = 4\).

Ответ: 4