Ответ:
а) \(4\frac{1}{6}+3\frac{2}{5}=7+\frac{5}{30}+\frac{12}{30}=7\frac{17}{30}\).
б) \(8\frac{3}{4}-7\frac{5}{6}=1+\frac{18}{24}-\frac{20}{24}=\frac{22}{24}=\frac{11}{12}\).
в) \(2\frac{11}{12}+6\frac{5}{8}=8+\frac{22}{24}+\frac{15}{24}=8\frac{37}{24}=9\frac{13}{24}\).
г) \(2\frac{13}{14}-1\frac{20}{21}=1+\frac{39}{42}-\frac{40}{42}=1\frac{-1}{42}=\frac{41}{42}\).
Ответ: а) \(7\frac{17}{30}\); б) \(\frac{11}{12}\); в) \(9\frac{13}{24}\); г) \(\frac{41}{42}\).
