Вопрос:

34. Выполните действия: а) \((3\frac{7}{30}-1\frac{5}{12}):18\frac{1}{6}\); б) \((1\frac{1}{2}+2\frac{2}{3}):1\frac{2}{3}\); в) \((\frac{11}{18}-1\frac{7}{12})\cdot(2\frac{1}{6}+\frac{7}{30})\); г) \((3\frac{2}{5}-5)\cdot(\frac{31}{48}+\frac{7}{24})\).

Ответ:

а)

\[\left(3\frac{7}{30}-1\frac{5}{12}\right):18\frac{1}{6}=\left(\frac{97}{30}-\frac{17}{12}\right):\frac{109}{6}\]

\[=\left(\frac{194}{60}-\frac{85}{60}\right)\cdot\frac{6}{109}=\frac{109}{60}\cdot\frac{6}{109}=\frac{1}{10}.\]

б)

\[\left(1\frac{1}{2}+2\frac{2}{3}\right):1\frac{2}{3}=\left(\frac{3}{2}+\frac{8}{3}\right):\frac{5}{3}\]

\[=\frac{25}{6}\cdot\frac{3}{5}=\frac{5}{2}=2\frac{1}{2}.\]

в)

\[\left(\frac{11}{18}-1\frac{7}{12}\right)\cdot\left(2\frac{1}{6}+\frac{7}{30}\right)=\left(\frac{11}{18}-\frac{19}{12}\right)\cdot\left(\frac{13}{6}+\frac{7}{30}\right)\]

\[=\left(\frac{22}{36}-\frac{57}{36}\right)\cdot\frac{72}{30}=\left(-\frac{35}{36}\right)\cdot\frac{12}{5}=-\frac{7}{3}=-2\frac{1}{3}.\]

г)

\[\left(3\frac{2}{5}-5\right)\cdot\left(\frac{31}{48}+\frac{7}{24}\right)=\left(\frac{17}{5}-5\right)\cdot\left(\frac{31}{48}+\frac{14}{48}\right)\]

\[=-\frac{8}{5}\cdot\frac{45}{48}=-\frac{8}{5}\cdot\frac{15}{16}=-\frac{3}{2}=-1\frac{1}{2}.\]

Ответ: а) \(\frac{1}{10}\); б) \(2\frac{1}{2}\); в) \(-2\frac{1}{3}\); г) \(-1\frac{1}{2}\).