35. The perimeter P of a square with side length s is given by P = 4s. The side length of square A is 4 times the side length of square B. How many times larger is the perimeter of square A than the perimeter of square B?

Пусть сторона квадрата B равна \(s\). Тогда сторона квадрата A равна \(4s\).

Периметр квадрата B:

\(P_B=4s\).

Периметр квадрата A:

\(P_A=4\cdot4s=16s\).

Отношение периметров:

\(\frac{P_A}{P_B}=\frac{16s}{4s}=4\).

Ответ: C) 4.