35. Вычислите \(\left(\frac{11}{45}-\frac{1}{9}\right)+\left(\frac{12}{15}-\frac{3}{10}\right)\).

\[\left(\frac{11}{45}-\frac{1}{9}\right)+\left(\frac{12}{15}-\frac{3}{10}\right)=\left(\frac{11}{45}-\frac{5}{45}\right)+\left(\frac{4}{5}-\frac{3}{10}\right)=\frac{6}{45}+\frac{8}{10}-\frac{3}{10}=\frac{2}{15}+\frac{1}{2}=\frac{4}{30}+\frac{15}{30}=\frac{19}{30}.\]

Ответ: \(\frac{19}{30}\).