Ответ:
Решение:
a)
\( -\frac{3}{4} - \left(-\frac{5}{6}\right) = -\frac{3}{4} + \frac{5}{6} = -\frac{3 \cdot 3}{4 \cdot 3} + \frac{5 \cdot 2}{6 \cdot 2} = -\frac{9}{12} + \frac{10}{12} = \frac{1}{12} \)
б)
\( 25 - 32 = -7 \)
в)
\( 3\frac{5}{6} - 4\frac{3}{8} = \frac{23}{6} - \frac{35}{8} = \frac{23 \cdot 4}{6 \cdot 4} - \frac{35 \cdot 3}{8 \cdot 3} = \frac{92}{24} - \frac{105}{24} = -\frac{13}{24} \)
г)
\( -3 - \frac{4}{9} = -\frac{3 \cdot 9}{9} - \frac{4}{9} = -\frac{27}{9} - \frac{4}{9} = -\frac{31}{9} \)
д)
\( -5,5 - 2,8 = -8,3 \)
е)
\( -7\frac{8}{9} - \left(-9\frac{1}{6}\right) = -7\frac{8}{9} + 9\frac{1}{6} = -\frac{71}{9} + \frac{55}{6} = -\frac{71 \cdot 2}{9 \cdot 2} + \frac{55 \cdot 3}{6 \cdot 3} = -\frac{142}{18} + \frac{165}{18} = \frac{23}{18} = 1\frac{5}{18} \)
Ответ: а) \(\frac{1}{12}\); б) -7; в) -\(\frac{13}{24}\); г) -\(\frac{31}{9}\); д) -8,3; е) \(1\frac{5}{18}\).
