Ответ:
Приводим дробные части к общему знаменателю, а при необходимости занимаем 1 у целой части.
- а) \(1-\frac{3}{4}=\frac{4}{4}-\frac{3}{4}=\frac{1}{4}\).
- б) \(2-\frac{5}{6}=\frac{12}{6}-\frac{5}{6}=\frac{7}{6}=1\frac{1}{6}\).
- в) \(9-\frac{11}{12}=8\frac{12}{12}-\frac{11}{12}=8\frac{1}{12}\).
- г) \(7-1\frac{7}{8}=5\frac{8}{8}-\frac{7}{8}=5\frac{1}{8}\).
- д) \(5-2\frac{2}{5}=2\frac{5}{5}-\frac{2}{5}=2\frac{3}{5}\).
- е) \(6-5\frac{5}{8}=\frac{8}{8}-\frac{5}{8}=\frac{3}{8}\).
- ж) \(8\frac{3}{11}-4=4\frac{3}{11}\).
- з) \(5\frac{7}{15}-\frac{3}{20}=5\frac{28}{60}-\frac{9}{60}=5\frac{19}{60}\).
- и) \(1\frac{5}{12}-\frac{9}{10}=1\frac{25}{60}-\frac{54}{60}=\frac{31}{60}\).
- к) \(6\frac{3}{10}-\frac{11}{15}=6\frac{9}{30}-\frac{22}{30}=5\frac{17}{30}\).
- л) \(5\frac{7}{8}-\frac{9}{10}=5\frac{35}{40}-\frac{36}{40}=4\frac{39}{40}\).
- м) \(7\frac{5}{12}-3\frac{2}{9}=4+\left(\frac{15}{36}-\frac{8}{36}\right)=4\frac{7}{36}\).
- н) \(10\frac{1}{2}-4\frac{9}{14}=5+\left(\frac{7}{14}+\frac{14}{14}-\frac{9}{14}\right)=5\frac{13}{14}\).
- о) \(7\frac{4}{7}-5\frac{7}{9}=6+\left(\frac{36}{63}+\frac{63}{63}-\frac{49}{63}\right)=6\frac{50}{63}\).
- п) \(2\frac{3}{10}-1\frac{11}{15}=\frac{9}{30}+\frac{30}{30}-\frac{22}{30}=1\frac{17}{30}\).
- р) \(5\frac{3}{8}-3\frac{5}{6}=1+\left(\frac{9}{24}+\frac{24}{24}-\frac{20}{24}\right)=1\frac{13}{24}\).
Ответ: а) \(\frac{1}{4}\); б) \(1\frac{1}{6}\); в) \(8\frac{1}{12}\); г) \(5\frac{1}{8}\); д) \(2\frac{3}{5}\); е) \(\frac{3}{8}\); ж) \(4\frac{3}{11}\); з) \(5\frac{19}{60}\); и) \(\frac{31}{60}\); к) \(5\frac{17}{30}\); л) \(4\frac{39}{40}\); м) \(4\frac{7}{36}\); н) \(5\frac{13}{14}\); о) \(6\frac{50}{63}\); п) \(1\frac{17}{30}\); р) \(1\frac{13}{24}\).
