Ответ:
Используем правило: \(\dfrac{\sqrt{a}}{\sqrt{b}}=\sqrt{\dfrac{a}{b}}\).
- а) \(\dfrac{\sqrt{2}}{\sqrt{18}}=\sqrt{\dfrac{2}{18}}=\sqrt{\dfrac{1}{9}}=\dfrac{1}{3}\).
- б) \(\dfrac{\sqrt{23}}{\sqrt{2300}}=\sqrt{\dfrac{23}{2300}}=\sqrt{\dfrac{1}{100}}=\dfrac{1}{10}\).
- в) \(\dfrac{\sqrt{52}}{\sqrt{117}}=\sqrt{\dfrac{4\cdot13}{9\cdot13}}=\sqrt{\dfrac{4}{9}}=\dfrac{2}{3}\).
- г) \(\dfrac{\sqrt{12500}}{\sqrt{500}}=\sqrt{\dfrac{12500}{500}}=\sqrt{25}=5\).
- д) \(\dfrac{\sqrt{7.5}}{\sqrt{0.3}}=\sqrt{\dfrac{7.5}{0.3}}=\sqrt{25}=5\).
Ответ: а) \(\dfrac{1}{3}\); б) \(\dfrac{1}{10}\); в) \(\dfrac{2}{3}\); г) 5; д) 5.
