Ответ:
- Ортақ көбейткіштерді қысқартамыз: \(\frac{2^3\cdot3^3\cdot5}{3^2\cdot2^3}=3\cdot5=15\).
- \(45=5\cdot9\), ал \(4^2=16\): \(\frac{45\cdot16}{80\cdot9}=\frac{5\cdot16}{80}=1\).
- \(16=2^4\), \(49=7^2\): \(\frac{7^3\cdot2^3}{2^4\cdot7^2}=\frac{7}{2}\).
- \(9=3^2\): \(\frac{11\cdot3^2\cdot5}{3^3\cdot11^2}=\frac{5}{3\cdot11}=\frac{5}{33}\).
- \(9=3^2\), \(25=5^2\): \(\frac{5^2\cdot3^3}{3^2\cdot5^2}=3\).
- \(87=3\cdot29\), \(25=5^2\): \(\frac{5^3\cdot29}{3\cdot29\cdot5^2}=\frac{5}{3}\).
Жауабы: 1) 15; 2) 1; 3) \(\frac{7}{2}\); 4) \(\frac{5}{33}\); 5) 3; 6) \(\frac{5}{3}\).
