Ответ:
Используем правило \(a:b=a\cdot\frac1b\).
а) \(\frac67:\frac56=\frac67\cdot\frac65=\frac{36}{35}=1\frac1{35}\); б) \(\frac4{15}:\frac{12}{23}=\frac4{15}\cdot\frac{23}{12}=\frac{23}{45}\); в) \(\frac8{21}:\frac{32}{49}=\frac8{21}\cdot\frac{49}{32}=\frac7{12}\); г) \(1\frac45:\frac3{10}=\frac95\cdot\frac{10}{3}=6\); д) \(\frac29:5=\frac29\cdot\frac15=\frac2{45}\).
е) \(\frac{18}{23}:5=\frac{18}{115}\); ё) \(3\frac17:5=\frac{22}{7}\cdot\frac15=\frac{22}{35}\); ж) \(\frac{24}{35}:5=\frac{24}{175}\); з) \(1\frac5{11}:\frac8{17}=\frac{16}{11}\cdot\frac{17}{8}=\frac{34}{11}=3\frac1{11}\); и) \(5\frac13:6\frac23=\frac{16}{3}\cdot\frac3{20}=\frac45\).
й) \(56:4\frac45=56:\frac{24}{5}=\frac{35}{3}=11\frac23\); к) \(27\frac67:3=\frac{195}{7}\cdot\frac13=\frac{65}{7}=9\frac27\); л) \(9\frac18:8\frac19=\frac{73}{8}\cdot\frac9{73}=\frac98=1\frac18\); м) \(\frac{18}{25}:2\frac25=\frac{18}{25}\cdot\frac5{12}=\frac3{10}\).
н) \(7\frac57:4\frac27=\frac{54}{7}\cdot\frac7{30}=\frac95=1\frac45\); о) \(12\frac35:9=\frac{63}{5}\cdot\frac19=\frac75=1\frac25\); п) \(40\frac{15}{17}:5=\frac{695}{17}\cdot\frac15=\frac{139}{17}=8\frac3{17}\); р) \(3\frac7{39}:1\frac5{31}=\frac{124}{39}\cdot\frac{31}{36}=\frac{31}{351}\cdot31?\) \(=\frac{961}{1404}\); с) \(\frac49:\frac38=\frac49\cdot\frac83=\frac{32}{27}=1\frac5{27}\); т) \(\frac37:\frac9{14}=\frac37\cdot\frac{14}{9}=\frac23\).
Ответ: \(1\frac1{35};\ \frac{23}{45};\ \frac7{12};\ 6;\ \frac2{45};\ \frac{18}{115};\ \frac{22}{35};\ \frac{24}{175};\ 3\frac1{11};\ \frac45;\ 11\frac23;\ 9\frac27;\ 1\frac18;\ \frac3{10};\ 1\frac45;\ 1\frac25;\ 8\frac3{17};\ \frac{961}{1404};\ 1\frac5{27};\ \frac23\).
