4. 67 + x = 2400 : 8 x - 143 = 18 ⋅ 3 x ⋅ 19 = 2000 – 100

Решение:

Решим каждое уравнение отдельно:

1. \( 67 + x = 2400 : 8 \)

\( 67 + x = 300 \)

\( x = 300 - 67 \)

\( x = 233 \)

2. \( x - 143 = 18 \cdot 3 \)

\( x - 143 = 54 \)

\( x = 54 + 143 \)

\( x = 197 \)

3. \( x \cdot 19 = 2000 - 100 \)

\( x \cdot 19 = 1900 \)

\( x = 1900 : 19 \)

\( x = 100 \)

Ответ: \( x = 233 \); \( x = 197 \); \( x = 100 \).