Ответ:
Формулы приведения:
1. Опорная точка \(\frac{\pi}{2}\) (\(n=1\))
- \(\sin\left(\frac{\pi}{2}-\alpha\right)=\cos\alpha\)
- \(\sin\left(\frac{\pi}{2}+\alpha\right)=\cos\alpha\)
- \(\cos\left(\frac{\pi}{2}-\alpha\right)=\sin\alpha\)
- \(\cos\left(\frac{\pi}{2}+\alpha\right)=-\sin\alpha\)
- \(\operatorname{tg}\left(\frac{\pi}{2}-\alpha\right)=\operatorname{ctg}\alpha\)
- \(\operatorname{tg}\left(\frac{\pi}{2}+\alpha\right)=-\operatorname{ctg}\alpha\)
- \(\operatorname{ctg}\left(\frac{\pi}{2}-\alpha\right)=\operatorname{tg}\alpha\)
- \(\operatorname{ctg}\left(\frac{\pi}{2}+\alpha\right)=-\operatorname{tg}\alpha\)
2. Опорная точка \(\pi\) (\(n=2\))
- \(\sin(\pi-\alpha)=\sin\alpha\)
- \(\sin(\pi+\alpha)=-\sin\alpha\)
- \(\cos(\pi-\alpha)=-\cos\alpha\)
- \(\cos(\pi+\alpha)=-\cos\alpha\)
- \(\operatorname{tg}(\pi-\alpha)=-\operatorname{tg}\alpha\)
- \(\operatorname{tg}(\pi+\alpha)=\operatorname{tg}\alpha\)
- \(\operatorname{ctg}(\pi-\alpha)=-\operatorname{ctg}\alpha\)
- \(\operatorname{ctg}(\pi+\alpha)=\operatorname{ctg}\alpha\)
3. Опорная точка \(\frac{3\pi}{2}\) (\(n=3\))
- \(\sin\left(\frac{3\pi}{2}-\alpha\right)=-\cos\alpha\)
- \(\sin\left(\frac{3\pi}{2}+\alpha\right)=-\cos\alpha\)
- \(\cos\left(\frac{3\pi}{2}-\alpha\right)=-\sin\alpha\)
- \(\cos\left(\frac{3\pi}{2}+\alpha\right)=\sin\alpha\)
- \(\operatorname{tg}\left(\frac{3\pi}{2}-\alpha\right)=\operatorname{ctg}\alpha\)
- \(\operatorname{tg}\left(\frac{3\pi}{2}+\alpha\right)=-\operatorname{ctg}\alpha\)
- \(\operatorname{ctg}\left(\frac{3\pi}{2}-\alpha\right)=\operatorname{tg}\alpha\)
- \(\operatorname{ctg}\left(\frac{3\pi}{2}+\alpha\right)=-\operatorname{tg}\alpha\)
4. Опорная точка \(2\pi\) (\(n=4\))
- \(\sin(2\pi-\alpha)=-\sin\alpha\)
- \(\sin(2\pi+\alpha)=\sin\alpha\)
- \(\cos(2\pi-\alpha)=\cos\alpha\)
- \(\cos(2\pi+\alpha)=\cos\alpha\)
- \(\operatorname{tg}(2\pi-\alpha)=-\operatorname{tg}\alpha\)
- \(\operatorname{tg}(2\pi+\alpha)=\operatorname{tg}\alpha\)
- \(\operatorname{ctg}(2\pi-\alpha)=-\operatorname{ctg}\alpha\)
- \(\operatorname{ctg}(2\pi+\alpha)=\operatorname{ctg}\alpha\)
