Ответ:
Подставим \(a=-3\):
\[\frac{28}{4(-3)-(-3)^2}-\frac{7}{-3}=\frac{28}{-12-9}+\frac{7}{3}=-\frac{28}{21}+\frac{7}{3}.\]
\[ -\frac{28}{21}+\frac{49}{21}=\frac{21}{21}=1.\]
Ответ: 1.
Подставим \(a=-3\):
\[\frac{28}{4(-3)-(-3)^2}-\frac{7}{-3}=\frac{28}{-12-9}+\frac{7}{3}=-\frac{28}{21}+\frac{7}{3}.\]
\[ -\frac{28}{21}+\frac{49}{21}=\frac{21}{21}=1.\]
Ответ: 1.