4. Решение:
\[ 7m^{-6} = \frac{7}{m^{6}} \]
\[ 2(ab)^{-1} = \frac{2}{ab} \]
\[ 11(x+y)^{-3} = \frac{11}{(x+y)^{3}} \]
\[ 9a^{3}b^{-4}c^{0} = 9a^{3}b^{-4} \cdot 1 = \frac{9a^{3}}{b^{4}} \]
\[ a^{-2} + b^{-1} = \frac{1}{a^{2}} + \frac{1}{b} = \frac{b+a^{2}}{a^{2}b} \]
\[ x^{0} + x^{-3} = 1 + \frac{1}{x^{3}} = \frac{x^{3}+1}{x^{3}} \]
\[ a + b^{-3} = a + \frac{1}{b^{3}} = \frac{ab^{3}+1}{b^{3}} \]
\[ xy^{-3} - x^{-1}y^{2} = \frac{x}{y^{3}} - \frac{y^{2}}{x} = \frac{x^{2} - y^{5}}{xy^{3}} \]