Ответ:\((4\sqrt{3}+\sqrt{27})\sqrt{3}=(4\sqrt{3}+3\sqrt{3})\sqrt{3}=7\sqrt{3}\cdot\sqrt{3}=21\).\((\sqrt{7}-\sqrt{3})^2=7-2\sqrt{21}+3=10-2\sqrt{21}\).Ответ: 1) \(21\); 2) \(10-2\sqrt{21}\).