Ответ:
\(1\frac{17}{55}=\frac{72}{55}\), поэтому \(11\cdot\frac{72}{55}=\frac{144}{10}=14,4\).
\(14,4-15,3=-0,9\).
\(3\frac{4}{7}=\frac{25}{7}\), \(4,5=\frac{9}{2}\), \(\frac{7}{35}=\frac{1}{5}\), \(8,75=\frac{35}{4}\).
Первое произведение: \(\frac{25}{7}\cdot\frac{9}{2}=\frac{225}{14}\).
Второе выражение: \(\frac{1}{5}\cdot\frac{35}{4}:\frac{2}{5}:\frac{9}{32}=\frac{7}{4}\cdot\frac{5}{2}\cdot\frac{32}{9}=\frac{140}{9}\).
\(\frac{225}{14}-\frac{140}{9}=\frac{75}{126}=\frac{25}{42}\).
\(2\frac{55}{76}=\frac{207}{76}\), поэтому \(19\cdot\frac{207}{76}=\frac{3933}{76}=51,75\).
\(51,75-39,4=12,35\).
\(3\frac{3}{25}=\frac{78}{25}\), \(5\frac{2}{5}=\frac{27}{5}\).
\(6,8\cdot\frac{5}{13}\cdot2,7\cdot\frac{78}{25}:\frac{27}{5}:\frac{1}{17}=68\).
Ответ: 1) \(-0,9\); 2) \(\frac{25}{42}\); 3) 12,35; 4) 68.
