Ответ:

  1. а) \(\left(\frac{1}{12}-\frac{17}{15}\right)\cdot\frac{10}{3}=\left(\frac{5}{60}-\frac{68}{60}\right)\cdot\frac{10}{3}=-\frac{63}{60}\cdot\frac{10}{3}=-\frac{21}{20}\cdot\frac{10}{3}=-\frac{7}{2}\).
  2. б) \(\left(2\frac{3}{17}+\frac{1}{34}\right)\cdot17=\left(\frac{74}{34}+\frac{1}{34}\right)\cdot17=\frac{75}{34}\cdot17=\frac{75}{2}=37{,}5\).