Вынесем общий множитель \(3\frac{1}{5}\):
\[3\frac{1}{5}\left(3\frac{3}{8}+1\frac{5}{12}-4\frac{1}{6}\right)=\frac{16}{5}\left(\frac{27}{8}+\frac{17}{12}-\frac{25}{6}\right).\]
\[\frac{27}{8}+\frac{17}{12}-\frac{25}{6}=\frac{81+34-100}{24}=\frac{15}{24}=\frac{5}{8}.\]
\[\frac{16}{5}\cdot\frac{5}{8}=2.\]
Ответ: 2.