Ответ:
- \(\frac{8-3c}{9c^2-64}=\frac{-(3c-8)}{(3c-8)(3c+8)}=-\frac{1}{3c+8}\).
- \(\frac{100-49b^2}{7b+10}=\frac{(10-7b)(10+7b)}{7b+10}=10-7b\).
- \(\frac{2y-10}{25-y^2}=\frac{2(y-5)}{(5-y)(5+y)}=-\frac{2}{y+5}\).
- \(\frac{5y-y^2}{25-y^2}=\frac{y(5-y)}{(5-y)(5+y)}=\frac{y}{y+5}\).
- \(\frac{b^2-c^2}{b^4n-c^4n}=\frac{(b-c)(b+c)}{n(b-c)(b+c)(b^2+c^2)}=\frac{1}{n(b^2+c^2)}\).
- \(\frac{5a^3b+5ab^3}{a^4-b^4}=\frac{5ab(a^2+b^2)}{(a-b)(a+b)(a^2+b^2)}=\frac{5ab}{a^2-b^2}\).
Ответ: 1) \(-\frac{1}{3c+8}\); 2) \(10-7b\); 3) \(-\frac{2}{y+5}\); 4) \(\frac{y}{y+5}\); 5) \(\frac{1}{n(b^2+c^2)}\); 6) \(\frac{5ab}{a^2-b^2}\).
