Ответ:
Используем правило: для ненулевого числа \(a\) справедливо \(a^{-n}=\frac{1}{a^n}\).
- \(11^{-2}=\frac{1}{11^2}=\frac{1}{121}\).
- \(6^{-3}=\frac{1}{6^3}=\frac{1}{216}\).
- \((-5)^{-4}=\frac{1}{(-5)^4}=\frac{1}{625}\).
- \((-4)^{-3}=\frac{1}{(-4)^3}=-\frac{1}{64}\).
- \(\left(-\frac{1}{9}\right)^{-1}=-9\).
- \(\left(\frac{5}{7}\right)^{-3}=\left(\frac{7}{5}\right)^3=\frac{343}{125}\).
- \(\left(-\frac{2}{5}\right)^{-2}=\left(-\frac{5}{2}\right)^2=\frac{25}{4}\).
- \(\left(1\frac{3}{4}\right)^{-1}=\left(\frac{7}{4}\right)^{-1}=\frac{4}{7}\).
- \(0,7^{-2}=\left(\frac{7}{10}\right)^{-2}=\left(\frac{10}{7}\right)^2=\frac{100}{49}\).
- \(1,2^{-2}=\left(\frac{6}{5}\right)^{-2}=\left(\frac{5}{6}\right)^2=\frac{25}{36}\).
Ответ: 1) \(\frac{1}{121}\); 2) \(\frac{1}{216}\); 3) \(\frac{1}{625}\); 4) \(-\frac{1}{64}\); 5) \(-9\); 6) \(\frac{343}{125}\); 7) \(\frac{25}{4}\); 8) \(\frac{4}{7}\); 9) \(\frac{100}{49}\); 10) \(\frac{25}{36}\).
