Ответ:

Bir xil sharoitda gazlarning zichligi molyar massasiga to‘g‘ri proporsional. Shuning uchun molyar massalarni solishtiramiz:

1) NO: 14 + 16 = 30 g/mol.

2) C₂H₂: 2 · 12 + 2 · 1 = 26 g/mol.

3) C₂H₆: 2 · 12 + 6 · 1 = 30 g/mol.

4) CO₂: 12 + 2 · 16 = 44 g/mol.

Javob: D) 1, 3 — NO va C₂H₆ ning molyar massalari teng, demak normal sharoitdagi zichliklari ham teng.