Ответ:
1)
Преобразуем смешанные числа в неправильные дроби:
\(2\frac{5}{9}=\frac{23}{9}\), \(1\frac{20}{21}=\frac{41}{21}\), \(1\frac{8}{49}=\frac{57}{49}\), \(1\frac{8}{9}=\frac{17}{9}\).
\[\left(\frac{23}{9}-\frac{41}{21}\right):\frac{57}{49}+\frac{17}{9}:6\]
\[\frac{23}{9}-\frac{41}{21}=\frac{161-123}{63}=\frac{38}{63}.\]
\[\frac{38}{63}:\frac{57}{49}=\frac{38}{63}\cdot\frac{49}{57}=\frac{14}{27}.\]
\[\frac{17}{9}:6=\frac{17}{54}.\]
\[\frac{14}{27}+\frac{17}{54}=\frac{28}{54}+\frac{17}{54}=\frac{45}{54}=\frac{5}{6}.\]
2)
Преобразуем смешанные числа:
\(1\frac{17}{18}=\frac{35}{18}\), \(1\frac{13}{14}=\frac{27}{14}\), \(2\frac{5}{8}=\frac{21}{8}\), \(1\frac{19}{20}=\frac{39}{20}\), \(2\frac{25}{78}=\frac{181}{78}\), \(1\frac{1}{26}=\frac{27}{26}\).
\[\frac{35}{18}\cdot\frac{27}{14}=\frac{15}{4}.\]
\[\frac{21}{8}:\frac{39}{20}=\frac{21}{8}\cdot\frac{20}{39}=\frac{35}{26}.\]
\[\frac{15}{4}-\frac{35}{26}=\frac{195-70}{52}=\frac{125}{52}.\]
\[\frac{181}{78}-\frac{27}{26}=\frac{181}{78}-\frac{81}{78}=\frac{50}{39}.\]
\[\frac{125}{52}:\frac{50}{39}=\frac{125}{52}\cdot\frac{39}{50}=\frac{15}{8}=1\frac{7}{8}.\]
Ответ: 1) \(\frac{5}{6}\); 2) \(\frac{15}{8}=1\frac{7}{8}\).
