Вопрос:
488. Вычислите: 1) \(2:\frac35+\frac35:2+1\frac12:6+6:1\frac12\); 2) \(6\frac14\cdot8-3\frac23\cdot5\frac12+2\frac25\cdot4\frac7{12}\); 3) \(2\frac12\cdot48-3\frac23:\frac1{18}+5\frac5{12}:\frac7{36}\); 4) \(13\frac12:1\frac13+16\frac12\cdot1\frac5{11}+19\frac14:\frac4{25}\).
Ответ:
- \[2:\frac35+\frac35:2+1\frac12:6+6:1\frac12=\frac{10}{3}+\frac3{10}+\frac14+4=\frac{239}{20}.\] Ответ: \(\frac{239}{20}\).
- \[\frac{25}{4}\cdot8-\frac{11}{3}\cdot\frac{11}{2}+\frac{12}{5}\cdot\frac{55}{12}=50-\frac{121}{6}+11=\frac{245}{6}.\] Ответ: \(\frac{245}{6}\).
- \[\frac52\cdot48-\frac{11}{3}:\frac1{18}+\frac{65}{12}:\frac7{36}=120-66+\frac{195}{7}=\frac{573}{7}.\] Ответ: \(\frac{573}{7}\).
- \[\frac{27}{2}:\frac43+\frac{33}{2}\cdot\frac{16}{11}+\frac{77}{4}:\frac4{25}=\frac{81}{8}+24+\frac{1925}{16}=\frac{2555}{16}.\] Ответ: \(\frac{2555}{16}\).
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