4x^2 - 20x + 25 = (3x + 1)^2

The equation is 4x^2 - 20x + 25 = (3x + 1)^2.

Expand the right side: (3x + 1)^2 = 9x^2 + 6x + 1.

The equation becomes 4x^2 - 20x + 25 = 9x^2 + 6x + 1.

Rearrange into a quadratic equation: 5x^2 + 26x - 24 = 0.

Using the quadratic formula x = [-b ± sqrt(b^2 - 4ac)] / 2a, where a=5, b=26, c=-24.

x = [-26 ± sqrt(26^2 - 4*5*(-24))] / (2*5)

x = [-26 ± sqrt(676 + 480)] / 10

x = [-26 ± sqrt(1156)] / 10

x = [-26 ± 34] / 10

Two solutions: x1 = ( -26 + 34 ) / 10 = 8 / 10 = 4/5

x2 = ( -26 - 34 ) / 10 = -60 / 10 = -6