Решение:
- \( \frac{1}{3} + \frac{5}{6} = \frac{2}{6} + \frac{5}{6} = \frac{7}{6} = 1\frac{1}{6} \)
- \( \frac{9}{10} - \frac{4}{5} = \frac{9}{10} - \frac{8}{10} = \frac{1}{10} \)
- \( \frac{11}{18} + \frac{1}{6} = \frac{11}{18} + \frac{3}{18} = \frac{14}{18} = \frac{7}{9} \)
- \( \frac{5}{12} - \frac{1}{2'} = \frac{5}{12} - \frac{6}{12} = -\frac{1}{12} \)
- \( \frac{5}{12} - \frac{5}{12} = 0 \)
- \( \frac{11}{21} + \frac{3}{7} = \frac{11}{21} + \frac{9}{21} = \frac{20}{21} \)
Ответ: a) \( 1\frac{1}{6} \), б) \( \frac{1}{10} \), д) \( \frac{7}{9} \), е) \( -\frac{1}{12} \), ж) 0, з) \( \frac{20}{21} \).