5) \(\frac{3,5+4\frac{2}{3}+2\frac{2}{15}}{1\frac{1}{20}+4,1}\)

Let's solve this problem step-by-step!

1. Numerator:
   • Convert all numbers to fractions with a common denominator. The least common multiple of 3, 15, and 20 is 60.

     \[ 3.5 = 3\frac{1}{2} = \frac{7}{2} = \frac{7 \times 30}{2 \times 30} = \frac{210}{60} \]

     \[ 4\frac{2}{3} = \frac{14}{3} = \frac{14 \times 20}{3 \times 20} = \frac{280}{60} \]

     \[ 2\frac{2}{15} = \frac{32}{15} = \frac{32 \times 4}{15 \times 4} = \frac{128}{60} \]

   • Add the fractions in the numerator:

     \[ \frac{210}{60} + \frac{280}{60} + \frac{128}{60} = \frac{618}{60} = \frac{103}{10} \]

2. Denominator:
   • Convert all numbers to fractions with a common denominator. The least common multiple of 20 and 10 is 20.

     \[ 1\frac{1}{20} = \frac{21}{20} \]

     \[ 4.1 = 4\frac{1}{10} = \frac{41}{10} = \frac{41 \times 2}{10 \times 2} = \frac{82}{20} \]

   • Add the fractions in the denominator:

     \[ \frac{21}{20} + \frac{82}{20} = \frac{103}{20} \]

3. Divide the numerator by the denominator:

   \[ \frac{103}{10} : \frac{103}{20} = \frac{103}{10} \times \frac{20}{103} = \frac{20}{10} = 2 \]

Answer: 2