5) $\left(\frac{29}{30}-\frac{9}{25}\right)\cdot\frac{9}{13}$ и $\left(\frac{1}{30}+\frac{4}{15}\right)\cdot\frac{29}{12}$

Question

Вопрос: $Фото задания: 5) $\left(\frac{29}{30}-\frac{9}{25}\right)\cdot\frac{9}{13}$ и $\left(\frac{1}{30}+\frac{4}{15}\right)\cdot\frac{29}{12}$$ Фото задания

5) $\left(\frac{29}{30}-\frac{9}{25}\right)\cdot\frac{9}{13}$ и $\left(\frac{1}{30}+\frac{4}{15}\right)\cdot\frac{29}{12}$

Accepted Answer

1) $\frac{29}{30}-\frac{9}{25}=\frac{145}{150}-\frac{54}{150}=\frac{91}{150}$.

$\frac{91}{150}\cdot\frac{9}{13}=\frac{7\cdot3}{50}=\frac{21}{50}$.

2) $\frac{1}{30}+\frac{4}{15}=\frac{1}{30}+\frac{8}{30}=\frac{3}{10}$.

$\frac{3}{10}\cdot\frac{29}{12}=\frac{29}{40}$.

Ответ: $\frac{21}{50}$ и $\frac{29}{40}$.

5) \(\left(\frac{29}{30}-\frac{9}{25}\right)\cdot\frac{9}{13}\) и \(\left(\frac{1}{30}+\frac{4}{15}\right)\cdot\frac{29}{12}\)

Ответ: