Ответ:\(\frac58x-\frac14x+\frac1{12}y+\frac13y=\frac38x+\frac5{12}y\).\(9.4y+2x-11\frac14y-3\frac59x=-\frac{32}{9}x-\frac{37}{40}y\).\(2\frac16y-7x+1\frac34y+2\frac15x=-\frac{24}{5}x+\frac{47}{12}y\).\(3.5x+6\frac14y-7x-7y=-3.5x-\frac34y\).