Ответ:

  1. \(\left(\frac{5}{22}-\frac{8}{11}\right)\cdot\frac{11}{5}=\left(\frac{5}{22}-\frac{16}{22}\right)\cdot\frac{11}{5}=-\frac{11}{22}\cdot\frac{11}{5}=-\frac{1}{2}\cdot\frac{11}{5}=-\frac{11}{10}\).
  2. \(\left(\frac{2}{5}+\frac{13}{15}\right)\cdot6=\left(\frac{6}{15}+\frac{13}{15}\right)\cdot6=\frac{19}{15}\cdot6=\frac{38}{5}\).
  3. \(\left(\frac{9}{16}+2\frac{3}{8}\right)\cdot4=\left(\frac{9}{16}+\frac{38}{16}\right)\cdot4=\frac{47}{16}\cdot4=\frac{47}{4}\).
  4. \(1\frac{4}{15}:\left(1\frac{11}{21}-2\frac{3}{7}\right)=\frac{19}{15}:\left(\frac{32}{21}-\frac{51}{21}\right)=\frac{19}{15}:\left(-\frac{19}{21}\right)=-\frac{21}{15}=-\frac{7}{5}\).
  5. \(15\cdot\left(\frac{1}{5}\right)^2-8\cdot\frac{1}{5}=15\cdot\frac{1}{25}-\frac{8}{5}=\frac{3}{5}-\frac{8}{5}=-1\).

Ответ: 1) \(-\frac{11}{10}\); 2) \(\frac{38}{5}\); 3) \(\frac{47}{4}\); 4) \(-\frac{7}{5}\); 5) \(-1\).