Ответ:
Смешанные числа сначала переводим в неправильные дроби, затем перемножаем и сокращаем.
1) \(2\frac{1}{3}\cdot\frac{3}{5}=\frac{7}{3}\cdot\frac{3}{5}=\frac{7}{5}=1\frac{2}{5}\).
2) \(1\frac{4}{7}\cdot2\frac{1}{3}=\frac{11}{7}\cdot\frac{7}{3}=\frac{11}{3}=3\frac{2}{3}\).
3) \(\frac{3}{4}\cdot1\frac{5}{6}=\frac{3}{4}\cdot\frac{11}{6}=\frac{11}{8}=1\frac{3}{8}\).
4) \(2\frac{2}{9}\cdot1\frac{1}{4}=\frac{20}{9}\cdot\frac{5}{4}=\frac{25}{9}=2\frac{7}{9}\).
5) \(5\frac{1}{2}\cdot\frac{3}{7}=\frac{11}{2}\cdot\frac{3}{7}=\frac{33}{14}=2\frac{5}{14}\).
6) \(1\frac{3}{8}\cdot4\frac{2}{3}=\frac{11}{8}\cdot\frac{14}{3}=\frac{77}{12}=6\frac{5}{12}\).
7) \(2\frac{5}{6}\cdot3\frac{3}{10}=\frac{17}{6}\cdot\frac{33}{10}=\frac{187}{20}=9\frac{7}{20}\).
8) \(1\frac{7}{12}\cdot2\frac{5}{9}=\frac{19}{12}\cdot\frac{23}{9}=\frac{437}{108}=4\frac{5}{108}\).
9) \(3\frac{1}{5}\cdot1\frac{3}{4}=\frac{16}{5}\cdot\frac{7}{4}=\frac{28}{5}=5\frac{3}{5}\).
10) \(4\frac{2}{3}\cdot2\frac{1}{2}=\frac{14}{3}\cdot\frac{5}{2}=\frac{35}{3}=11\frac{2}{3}\).
11) \(2\frac{4}{5}\cdot1\frac{5}{6}=\frac{14}{5}\cdot\frac{11}{6}=\frac{77}{15}=5\frac{2}{15}\).
12) \(\frac{6}{11}\cdot3\frac{2}{7}=\frac{6}{11}\cdot\frac{23}{7}=\frac{138}{77}=1\frac{61}{77}\).
