Ответ:
Используем биномиальную формулу: \((u+v)^n=\sum_{k=0}^{n}C_n^k u^{n-k}v^k\).
- \((1+x)^8=1+8x+28x^2+56x^3+70x^4+56x^5+28x^6+8x^7+x^8\).
- \((x+1)^7=x^7+7x^6+21x^5+35x^4+35x^3+21x^2+7x+1\).
- \((a-1)^9=a^9-9a^8+36a^7-84a^6+126a^5-126a^4+84a^3-36a^2+9a-1\).
- \((y-1)^{10}=y^{10}-10y^9+45y^8-120y^7+210y^6-252y^5+210y^4-120y^3+45y^2-10y+1\).
- \((2x+1)^5=32x^5+80x^4+80x^3+40x^2+10x+1\).
- \((x+2)^6=x^6+12x^5+60x^4+160x^3+240x^2+192x+64\).
- \((3x+2)^4=81x^4+216x^3+216x^2+96x+16\).
- \((2a+3)^5=32a^5+240a^4+720a^3+1080a^2+810a+243\).
- \((2a-\frac12)^5=32a^5-40a^4+20a^3-5a^2+\frac58a-\frac1{32}\).
- \((3x-\frac13)^4=81x^4-36x^3+6x^2-\frac49x+\frac1{81}\).
