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МатематикаВопрос:
52) 1/x^2 + 2/x - 3 = 0;
Ответ:
1. Multiply by x^2: 1 + 2x - 3x^2 = 0.
2. Rearrange into quadratic form: 3x^2 - 2x - 1 = 0.
3. Factor and solve: (3x+1)(x-1) = 0 -> x = 1, x = -1/3. (Note: x cannot be 0).
Похожие
- 1) x + x/3 = 8;
- 4) x/8 + x/11 = -19/11;
- 7) 6 - x/2 = x/3;
- 10) x/6 + x/12 + x = -35/4;
- 13) 8 + x = (x+2)/7;
- 16) (2x+5)/6 + 4 = 4x/7;
- 19) (5x-5)/3 - 2x = 2;
- 22) 10/(x+6) = -5/3;
- 25) 11/(x-5) = 5/(x-11);
- 28) 1/(x+7) + 1/(x-3) = 0;
- 31) 2/(x-6) = -5;
- 34) 13/(x-12) + 12/(x-13) = 2;
- 37) (x-5)/(x-9) = 5;
- 40) (x-11)/(x-12) = 11/10;
- 43) x - 12/x = 4;
- 46) (x^2 - 3x - 4)/(x+1) = 0;
- 49) (2x^2 - 4x)/(x+6) = 0;
