Ответ:

  1. \(4\frac{1}{12}-\frac{1}{6}=4+\frac{1}{12}-\frac{2}{12}=3\frac{11}{12}\).
  2. \(9\frac{11}{24}-7\frac{19}{36}=2+\frac{33}{72}-\frac{38}{72}=1\frac{67}{72}\).
  3. \(5\frac{5}{9}-2\frac{4}{7}=3+\frac{35}{63}-\frac{36}{63}=2\frac{62}{63}\).
  4. \(9\frac{8}{35}-2\frac{52}{105}=7+\frac{24}{105}-\frac{52}{105}=6\frac{77}{105}=6\frac{11}{15}\).
  5. \(8\frac{6}{35}-6\frac{7}{10}=2+\frac{12}{70}-\frac{49}{70}=1\frac{33}{70}\).
  6. \(9\frac{5}{14}-3\frac{27}{49}=6+\frac{35}{98}-\frac{54}{98}=5\frac{79}{98}\).

Ответ: 1) \(3\frac{11}{12}\); 2) \(1\frac{67}{72}\); 3) \(2\frac{62}{63}\); 4) \(6\frac{11}{15}\); 5) \(1\frac{33}{70}\); 6) \(5\frac{79}{98}\).