Ответ:

  1. \(\frac49+\frac79-\frac19=\frac{4+7-1}{9}=\frac{10}{9}=1\frac19\).

  2. \(\frac67-\left(\frac57-\frac17\right)=\frac67-\frac47=\frac27\).

  3. \(5\frac6{39}+4\frac7{78}=9+\frac{12}{78}+\frac7{78}=9\frac{19}{78}\).

  4. \(7\frac{13}{15}-8\frac{11}{30}=7\frac{26}{30}-8\frac{11}{30}=-1\frac{15}{30}=-1\frac12\).

  5. \(\frac78\cdot\frac4{35}\cdot\frac{10}{9}=\frac19\).

  6. \(\left(\frac12:\frac34-\frac49\right)\cdot\frac53=\left(\frac23-\frac49\right)\cdot\frac53=\frac29\cdot\frac53=\frac{10}{27}\).

Ответ: а) \(1\frac19\); б) \(\frac27\); в) \(9\frac{19}{78}\); г) \(-1\frac12\); д) \(\frac19\); е) \(\frac{10}{27}\).