e) (\frac{3}{7} - \frac{1}{7})^2 \cdot \frac{49}{16} + (\frac{1}{2})^3 = (\frac{2}{7})^2 \cdot \frac{49}{16} + \frac{1}{8} = \frac{4}{49} \cdot \frac{49}{16} + \frac{1}{8} = \frac{4}{16} + \frac{1}{8} = \frac{1}{4} + \frac{1}{8} = \frac{2}{8} + \frac{1}{8} = \frac{3}{8}