Ответ:
а) \(\left(1\frac{2}{9}+1\frac{1}{6}\right)\left(2-1\frac{25}{42}\right)=\left(\frac{11}{9}+\frac{7}{6}\right)\left(\frac{84}{42}-\frac{67}{42}\right)=\frac{43}{18}\cdot\frac{17}{42}=\frac{731}{756}\).
б) \(\left(4+2\frac{7}{15}\right)\left(10-8\frac{16}{23}\right)=\frac{97}{15}\cdot\frac{30}{23}=\frac{194}{23}=8\frac{10}{23}\).
в) \(\left(4+5\frac{1}{6}\right)\left(3\frac{2}{3}-\frac{13}{33}\right)=\frac{55}{6}\cdot\left(\frac{121}{33}-\frac{13}{33}\right)=\frac{55}{6}\cdot\frac{36}{11}=30\).
г) \(6\frac{5}{12}\cdot\frac{4}{11}-11\frac{1}{4}\cdot\frac{1}{9}=\frac{77}{12}\cdot\frac{4}{11}-\frac{45}{4}\cdot\frac{1}{9}=\frac{7}{3}-\frac{5}{4}=\frac{13}{12}=1\frac{1}{12}\).
Ответ: а) \(\frac{731}{756}\); б) \(8\frac{10}{23}\); в) 30; г) \(1\frac{1}{12}\).
