Ответ:
- Приведём дроби к знаменателю 48: \(6\frac{7}{8}=6\frac{42}{48}\), \(3\frac{1}{3}=3\frac{16}{48}\), \(5\frac{5}{16}=5\frac{15}{48}\).
\(6\frac{42}{48}-3\frac{16}{48}+5\frac{15}{48}=8\frac{41}{48}\). - \(2\frac{3}{7}=2\frac{6}{14}\), поэтому \(5\frac{9}{14}-2\frac{6}{14}=3\frac{3}{14}\).
\(6,7=6\frac{7}{10}\), тогда \(3\frac{3}{14}+6\frac{7}{10}=9\frac{26}{35}\). - \(15\frac{5}{6}=15\frac{135}{162}\), \(9\frac{25}{27}=9\frac{150}{162}\), \(2\frac{17}{18}=2\frac{153}{162}\).
\(15\frac{135}{162}-9\frac{150}{162}=5\frac{147}{162}=5\frac{49}{54}\).
\(5\frac{49}{54}-2\frac{17}{18}=3\frac{49}{54}-\frac{51}{54}=3\frac{25}{27}\). - \(18-10\frac{5}{9}=7\frac{4}{9}\).
\(6\frac{1}{8}-3\frac{2}{3}=2\frac{11}{24}\).
\(7\frac{4}{9}-2\frac{11}{24}=4\frac{29}{72}\).
Ответ: 1) \(8\frac{41}{48}\); 2) \(9\frac{26}{35}\); 3) \(3\frac{25}{27}\); 4) \(4\frac{29}{72}\).
