Давай разберем первое задание:
3 \(\frac{18}{28}\) = \(\frac{3 \times 28 + 18}{28}\) = \(\frac{84 + 18}{28}\) = \(\frac{102}{28}\)
\(\frac{102}{28}\) = \(\frac{51}{14}\) (делим числитель и знаменатель на 2)
\(\frac{6}{12}\) : \(\frac{51}{14}\)
\(\frac{6}{12}\) \(\times\) \(\frac{14}{51}\)
\(\frac{6}{12}\) \(\times\) \(\frac{14}{51}\) = \(\frac{1}{2}\) \(\times\) \(\frac{14}{51}\) = \(\frac{1 \times 14}{2 \times 51}\) = \(\frac{14}{102}\)
\(\frac{14}{102}\) = \(\frac{7}{51}\) (делим числитель и знаменатель на 2)
Ответ: 7/51